![i) If a^(2)+b^(2)+c^(2)=20 " and" a+b+c=0, " find " ab+bc+ac. (ii) If a^(2)+ b^(2)+c^(2)=250 " and" ab+bc+ca i) If a^(2)+b^(2)+c^(2)=20 " and" a+b+c=0, " find " ab+bc+ac. (ii) If a^(2)+ b^(2)+c^(2)=250 " and" ab+bc+ca](https://d10lpgp6xz60nq.cloudfront.net/question-thumbnail/en_644858337.png)
i) If a^(2)+b^(2)+c^(2)=20 " and" a+b+c=0, " find " ab+bc+ac. (ii) If a^(2)+ b^(2)+c^(2)=250 " and" ab+bc+ca
![The determinant |{:(b^2-ab, b-c, bc-ac), (a b-a^2, a-b, b^2-ab) ,(b c-c a, c-a, a b-a^2):}| equals a b c\ (b-c The determinant |{:(b^2-ab, b-c, bc-ac), (a b-a^2, a-b, b^2-ab) ,(b c-c a, c-a, a b-a^2):}| equals a b c\ (b-c](https://d10lpgp6xz60nq.cloudfront.net/ss/web/731558.jpg)
The determinant |{:(b^2-ab, b-c, bc-ac), (a b-a^2, a-b, b^2-ab) ,(b c-c a, c-a, a b-a^2):}| equals a b c\ (b-c
Using properties of determinants, prove that |(-bc,b^2+bc,c^2+bc)(a^2+ac,-ac ,c^2+ac)(a^2+ab,b^2+ab,-ab)| = (ab+bc+ac)^3. - Sarthaks eConnect | Largest Online Education Community
![la? a? -(b - c)2 bc b2b2 -(c - a) ca = (a - b) (b -c) (c-a) (a + b + c) (22 +62 + ?) c2c2-(a - b)2 ab la? a? -(b - c)2 bc b2b2 -(c - a) ca = (a - b) (b -c) (c-a) (a + b + c) (22 +62 + ?) c2c2-(a - b)2 ab](https://instasolv1.s3.ap-south-1.amazonaws.com/QuestionBank/5ce4d9f97518a40e6cb7b295/solution_image.png?version=1)
la? a? -(b - c)2 bc b2b2 -(c - a) ca = (a - b) (b -c) (c-a) (a + b + c) (22 +62 + ?) c2c2-(a - b)2 ab
How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all values of [math] a, b,[/math] and [math]c - Quora
![if b c b c c a c a a b a b are in ap then show that 1 b c 1 c a 1 a b are in ap use add ab bc ca a 2 b 2 c 2 to each term - Mathematics - TopperLearning.com | m282cbrr if b c b c c a c a a b a b are in ap then show that 1 b c 1 c a 1 a b are in ap use add ab bc ca a 2 b 2 c 2 to each term - Mathematics - TopperLearning.com | m282cbrr](https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=c8cae624f00ad36dffe9ec9a3da022c3.png)
if b c b c c a c a a b a b are in ap then show that 1 b c 1 c a 1 a b are in ap use add ab bc ca a 2 b 2 c 2 to each term - Mathematics - TopperLearning.com | m282cbrr
Using properties of determinants, prove that |(a,b,c)(a2,b2,c2)(bc,ca,ca)| = (a-b)(b-c)(c-a)(ab+bc+ca) - Sarthaks eConnect | Largest Online Education Community
![radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange](https://i.stack.imgur.com/UVS3U.png)
radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange
How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all values of [math] a, b,[/math] and [math]c - Quora
![if a2 b2 c2 30 and a b c 10 then find the value of ab bc ca - Mathematics - TopperLearning.com | 13911 if a2 b2 c2 30 and a b c 10 then find the value of ab bc ca - Mathematics - TopperLearning.com | 13911](http://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=2dc373a199c2e2a37df3680dd9282178.png)